-12x^2-20=-32x

Solution for -12x^2-20=-32x equation:

-12x^2-20=-32x

We move all terms to the left:

-12x^2-20-(-32x)=0

We get rid of parentheses

-12x^2+32x-20=0

a = -12; b = 32; c = -20;
Δ = b2-4ac
Δ = 322-4·(-12)·(-20)
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{64}=8$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(32)-8}{2*-12}=\frac{-40}{-24}
=1+2/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(32)+8}{2*-12}=\frac{-24}{-24}
=1
$